[tex]AlBr_3[/tex] is a neutral molecule. which means the sum of oxidation numbers of all atoms is zero Bromine has a charge of -1. There are 3Br atoms that are added on [tex]Al^+^3[/tex] to give a neutral charge of 0.
[tex]1Al[/tex] atom+ [tex]3Br[/tex] atoms produce an electrically neutral salt.
This means there is only one [tex]Al^+^3[/tex] needed to form the salt.
Answer: The number of [tex]Al^{3+}[/tex] ions in given compound is [tex]6.022\times 10^{23}[/tex]
Explanation:
We are given:
A chemical compound having chemical formula [tex]AlBr_3[/tex]
It is an ionic compound. This compound is formed by the complete transfer of electrons from 1 atom to another atom. The cation is formed by the loss of electrons by metals and anions are formed by gain of electrons by non metals.
It is formed by the combination of 1 aluminium ion and 3 bromine ions.
According to mole concept:
1 mole of an ionic compound contains [tex]6.022\times 10^{23}[/tex] number of ions.
So, 1 mole of [tex]AlBr_3[/tex] will contain [tex](1\times 1\times 6.022\times 10^{23})=6.022\times 10^{23}[/tex] number of aluminium ions
Hence, the number of [tex]Al^{3+}[/tex] ions in given compound is [tex]6.022\times 10^{23}[/tex]
