Ray weighs 100 kilograms, his wrestling partner, Bobby, weighs 50 kilograms. If Ray moves at 4 m s , how fast will Bobby have to run at him to apply an equal amount of kinetic energy?

Respuesta :

Both Ray and his wrestling partner have kinetic energy by virtue of them moving. Ray has a mass  [tex]m=100kg[/tex] , velocity     [tex]v=4m/s[/tex].  Ray's kinetic energy is calculated as follows,

[tex]KE=\frac{1}{2} mv^2=\frac{1}{2} \times 100kg\times (4m/s)^2=800 J.[/tex]

Bobby wishes to archive the same amount of kinetic energy as Ray. To find what his velocity should be, we have to solve for    [tex]v[/tex] in the kinetic energy formula. For Bobby,      [tex]KE=800J[/tex], mass  [tex]m=50kg[/tex].

So,

[tex]KE=\frac{1}{2} mv^2\\=>800J=\frac{1}{2} \times 50v^2\\=>v^2=\frac{1600J}{50kg} \\\\=>v=\sqrt{\frac{1600J}{50kg}} =5.66m/s[/tex] .

This means for Bobby to have the same kinetic energy as Ray, he has to run at [tex]5.66m/s.[/tex]

Answer:  C) 5.65 m/s

Explanation: usatestprep ..