Answer : B. 0 m/s∧2
Now we know that velocity = distance/ time
And acceleration = velocity/time.
From the graph we see that at the time interval 2 secs,the distance travelled is 10 m. Hence the velocity(v1) =10/2 = 5m/s.
From the graph we see that at the time interval 5 secs,the distance travelled is 25 m. Hence the velocity (v2) =25/5 = 5m/s.
Now acceleceration between the time interval of 2 ad 5 secs is calculated as
(v1-v2)/t2-t1 = (5-5)/(5-2) = 0 m/s∧2
