Hello!
What is the heat required to vaporize 650 grams of a liquid with a heat of vaporization of 723 joules/gram?
We have the following data:
[tex]H_v\:(heat\:of\:vaporization) = 723\:\dfrac{J}{g}[/tex]
[tex]q\:(heat) =\:?\:(in\:Joule)[/tex]
[tex]m\:(mass) = 650\:g[/tex]
We apply the data to the formula, see:
[tex]H_v = \dfrac{q}{m}[/tex]
[tex]q = H_v * m[/tex]
[tex]q = 723\:\dfrac{J}{\diagup\!\!\!\!g} * 650\:\diagup\!\!\!\!\!g[/tex]
[tex]q = 469,950 \to \boxed{\boxed{q \approx 470,000\:J}}\end{array}}\qquad\checkmark[/tex]
Answer:
E. 470,000 J
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I Hope this helps, greetings ... Dexteright02! =)
