Given vertices of parallelogram ABCD:
A(−10,6), B(−5.5,26), C(9.5,18), and D(5,−2).
Length of AB is :
[tex]=\sqrt{\left(-5.5-\left(-10\right)\right)^2+\left(26-6\right)^2}= 20.5[/tex].
Length of BC is :
[tex]=\sqrt{\left(9.5-\left(-5.5\right)\right)^2+\left(18-26\right)^2} =17.[/tex]
Note, opposite sides of a parallelogram are equal.
Therefore,
Perimeter of parallelogram ABCD = 2 × Length of AB + 2 × Length of BC.
Perimeter = 2 × 20.5 + 2 × 17
= 41 + 34
= 75 units.
