Answer: sec θ = [tex]\frac{3}{2}[/tex]
Step-by-step explanation:
cos θ = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{2}{3}[/tex]
sec θ = [tex]\frac{hypotenuse}{adjacent}[/tex] = [tex]\frac{3}{2}[/tex]
Extra Credit: Use Pythagorean Theorem to find the opposite side
2² + b² = 3²
4 + b² = 9
b² = 5
b = √5
sin θ = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{\sqrt{5}}{3}[/tex]
csc θ = [tex]\frac{hypotenuse}{opposite}[/tex] = [tex]\frac{3}{\sqrt{5}}[/tex] = [tex]\frac{3\sqrt{5}}{5}}[/tex]
