Answer: [tex]\frac{32}{9}[/tex]
Step-by-step explanation:
C = πd
Circle A: C = 2[tex]\frac{2}{3}[/tex] = [tex]\frac{8}{3}[/tex]
[tex]\frac{8}{3}[/tex] = πd
÷π ÷π
[tex]\frac{8}{3\pi}[/tex] = d
Circle B: d = 1[tex]\frac{1}{3}[/tex](diameter of Circle A)
= [tex]\frac{4}{3}[/tex][tex](\frac{8}{3\pi})[/tex]
= [tex]\frac{32}{9\pi}[/tex]
C = πd
= π[tex](\frac{32}{9\pi})[/tex]
= [tex]\frac{32}{9}[/tex]
