babymonk21605
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What is the equation, in point-slope form, for a line that goes through (8,-4) and has a slope of -5/6?

y+4=-5/6(x-8)

y-4=-5/6(x+8)

y+4=-5/6(x+8)

y-4=-5/6(x-8)

Respuesta :

gmany

The point-slope form:

[tex]y-y_1=m(x-x_1)[/tex]

We have the point (8, -4) and the slope m = -5/6. Substitute:

[tex]y-(-4)=-\dfrac{5}{6}(x-8)\\\\\boxed{y+4=-\dfrac{5}{6}(x-8)}[/tex]

aspena9227

Answer:

Y+4=-5/6(x-8)

Step-by-step explanation:

Ver imagen aspena9227

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