[tex]\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 1.5\%\to \frac{1.5}{100}\dotfill &0.015\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &10 \end{cases}[/tex]
[tex]\bf A=5000\left(1+\frac{0.015}{12}\right)^{12\cdot 10}\implies A=5000(1.00125)^{120}\implies A\approx 5808.62708[/tex]
