Respuesta :
E = (1/2)mv²
1800 = (1/2)(70)v²
Solving for v²
1800(2)/70 = v²
v² = 55.714
√v² = √55.714
v = ~7.46 m/s
Answer:
Kinetic energy = 1800 J
Explanation:
As per work energy theorem we know that the total work done on the system is always equal to the change in kinetic energy of the system
So we can say it as
[tex]W_{net} = KE_f - KE_i[/tex]
here we can say that initially it starts from the rest state so the initial kinetic energy is given as
[tex]KE_i = 0[/tex]
now from above equation we can say
[tex]W_{net} = KE_f - 0[/tex]
so final kinetic energy must be equal to net work done on it
kinetic energy = 1800 J
