The given equation is:
[tex]\frac{x+3}{2}= \frac{3x+5}{5}[/tex]
Cross multiplication would have given us
[tex]5(x+3)=2(3x+5)[/tex]..................(Equation 1)
Now, if we use the multiplication property of equality to multiply both sides of the equation by 10, we will get:
[tex]\frac{x+3}{2}\times 10= \frac{3x+5}{5}\times 10[/tex]
This will become [tex]5(x+3)=2(3x+5)[/tex], which is the same as (Equation 1) which we had got from cross multiplication.
Thus, out of the given options, the third option, "using the multiplication property of equality to multiply both sides of the equation by 10" is the correct one.
