a 12-foot board rests against a wall. The angle that the board makes with the ground is 60. How far is the base of the board away from the wall?

Respuesta :

Answer:

ground = 6.928 ft

Step-by-step explanation:

tan 60 = opposite/ adjacent

tan 60 =12/ ground

multiply by ground

ground * tan 60 = 12

divide by tan 60

ground = 12/tan 60

ground = 6.928 ft

Answer:

6 foot away

Step-by-step explanation:

A board AC with measure of 12 foot rests against the wall.

The angle that board makes with the ground is 60°

Then we have to calculate the distance ( BC) of board from the wall.

Cos 60° = [tex]\frac{BC}{AC}[/tex]

[tex]\frac{1}{2}[/tex] =  [tex]\frac{BC}{12}[/tex]

BC =  [tex]\frac{12}{2}[/tex]

     = 6 foot

Therefore, board is 6 foot away from the wall.

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