There are 2 spinners. One spinner has four equally sized sectors that are numbered 1, 2, 3, and 4. The 2nd spinner has 3 equally size sectors that are labeled A, B, and C. Each spinner is spun once how many outcomes do not show an even number?

1. Multiply the number of out comes from each spinner. The spinner with numbers has four different numbers which means four different outcomes. The second spinner with letters has three different letters which means three different outcomes.

4x3=12

2. Since their are two even and two odd numbers on the first spinner, for this problem you can simply divide the total number of outcomes(12) by 2.

12/2=6

6 outcomes with odd numbers(without even numbers)

6 outcomes with even numbers

jcherry99 jcherry99 · Answer 2 · 2018-12-01T21:06:18+01:00

jcherry99 jcherry99

01-12-2018

Answer:

2

Step-by-step explanation:

It does not matter what the letters do. So it all comes down to what the numbered spinner does.

2 numbers are not even. The answer should be 2, but don't be surprised if someone tells you that the letters do matter. (They don't).

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