Answer:
a) T=181°F
b) T=78.469°F
Step-by-step explanation:
In this case big T is temperature and little t is time in minutes, in physics this is usually the case.
Now for the initial temperature time is zero minutes so:
Let t=0
[tex]T(0)=76+105e^{-0.125(0)}\\\\T(0)=76+105=181[/tex]
And so the initial temperature of the soup is 181°F.
The temperature after 30 minutes is:
Let t=30
[tex]T(30)=76+105e^{-0.125(30)}\\\\=76+105e^{-3.75}\\\\=78.469[/tex]
So the temperature after 30 minutes is 78.469°F. If you have a graphing calculator replace T(t) with y and t with x and look at when x=0 and x=30 your y will represent temperature.
