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Carbon dating of small bits of charcoal used in cave paintings has determined that some of the paintings are from 10000 to 30000 y old. Carbon-14 has a half-life of 5730 y. In a 1μg-sample of carbon from a live tree, the activity of carbon-14 is 6.4μCi. If researchers determine that 1μg of charcoal from a prehistoric cave painting in France has an activity of 0.80 μCi, what is the age of the painting?

Respuesta :

The age of painting was determined from the decay kinetics of the radioactive Carbon -14 present in the painting sample.

Given that the half life of Carbon-14 is 5730 years.

Radioactive decay reactions follow first order rate kinetics.

Calculating the decay constant from half life:

λ[tex]= \frac{0.693}{t_{1/2} }[/tex]

        = [tex]\frac{0.693}{5730 yr}[/tex] = [tex]1.21*10^{-4}yr^{-1}[/tex]

Setting up the radioactive rate equation:

[tex]ln\frac{A_{t} }{A_{0} } =-kt[/tex]

Where [tex]A_{t} = Activity after time t = 0.80microCi[/tex]

[tex]A_{t} = initial activity = 6.4microCi[/tex]

k = decay constant = [tex]1.21*10^{-4}yr^{-1}[/tex]

[tex]ln\frac{0.80uCi}{6.4uCi} =-(1.21*10^{-4}yr^{-1})t[/tex]

ln 0.125 = [tex]-(1.21*10^{-4}yr^{-1})t[/tex]

-2.079=[tex]-(1.21*10^{-4}yr^{-1})t[/tex]

t=[tex]\frac{2.07944}{1.21*10^{-4} } yr[/tex]

 = 17185 years

t = 17185 years

Therefore age of the painting based in the radiocarbon -14 dating studies is 17185 years