Answer:
455 kg m/s
Explanation:
The impulse acted on the object is equal to the change in momentum of the object:
[tex]I=\Delta p[/tex]
and the change in momentum is equal to the product between the mass of the object and the change in velocity:
[tex]\Delta p=m \Delta v=m (v-u)[/tex]
where:
m = 25 kg is the mass of the object
u = 12 m/s is the initial velocity of the object
v = -6.2 m/s is the final velocity of the object (we have taken a negative sign because the object now moves in the opposite direction)
Therefore, the impulse is
[tex]I=\Delta p=m(v-u)=(25 kg)(12 m/s-(-6.2 m/s))=455 kg m/s[/tex]
