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PLEASE HELP!!! (50pts + Correct and best gets brainliest)

In the diagram below, DE and EF are tangent to O. Which equation could be solved to find X, the measure of DF?

A. 1/2(228 + 48) = x
B. 1/2(228 - 48) = x
C. 1/2(228 + x) = 48
D. 1/2(228 - x) = 48

PLEASE HELP 50pts Correct and best gets brainliest In the diagram below DE and EF are tangent to O Which equation could be solved to find X the measure of DF A class=

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wegnerkolmp2741o

Answer:

D. 1/2(228 - x) = 48


Step-by-step explanation:

<e = 1/2(dgf-df)

48 = 1/2(228-x)

Answer:

x = 132.

Step-by-step explanation:

Given information: DE and EF are tangent to O.

According to the two tangent theorem, if two tangent intersect each other then the angle form by them is half of the difference of major arc and minor arc.

Using the two tangent theorem, we get

[tex]\angle DE F=\dfrac{1}{2}(\widehat{DGF}-\widehat{DF}})[/tex]

[tex]48=\dfrac{1}{2}(228-x)[/tex]

Multiply both sides by 2.

[tex]96=228-x[/tex]

[tex]96-228=-x[/tex]

[tex]-132=-x[/tex]

Multiply both sides by -1.

[tex]132=x[/tex]

Therefore, the value of x is 132.

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