Hello from MrBillDoesMath!
Answer: Choice C
Discussion:
Let's looks at things one case at a time:
A. The value 1 lies in set A but 2x^2 + 5x -3 at x = 1, = 2(1)^2 + 5*1 -3 =4 which is NOT <=0
B. As in choice A, the value x = 1 lies in set B but does not does not yield 2x^2 + 5x -3 <= 0
So C is the only remaining option.
Alternate approach.
Factor the polynomial:
2x^2 + 5x -3 = (2x-1) (x + 3)
so for 2x^2 + 5x -3 <= 0
one of the factors must be positive and the other negative. Do the analysis and you will get choice C as the answer
Thank you,
MrB
