Respuesta :
Answer : The percent of aluminium in [tex]Al_2(SO_4)_3[/tex] is [tex]15.77\%[/tex]
Solution :
Molar mass of Aluminium = 26.98 g/mole
Molar mass of [tex]Al_2(SO_4)_3[/tex] = 342.15 g/mole
First we have to calculate the mass of Aluminium.
Mass of 2 Al atoms = 2 × 26.98 g/mole = 53.96 g/mole
Now we have to calculate the percent composition of Aluminium in [tex]Al_2(SO_4)_3[/tex]
[tex]\%\text{ of Al}=\frac{\text{ Mass of Al}}{\text{ Total mass}}\times 100[/tex]
Now put all the given values in this formula, we get
[tex]\%\text{ of Al}=\frac{53.96g/mole}{342.15g/mole}\times 100[/tex]
[tex]\%\text{ of Al}=15.77\%[/tex]
Therefore, the percent of aluminium in [tex]Al_2(SO_4)_3[/tex] is [tex]15.77\%[/tex]
