Mason bought 6 loaves of bread and 3 packages of cheese for a total of $27. The cost of a package of cheese is $1.50 more than the cost of a one loaf of bread. What is the combined cost of one loaf of bread and one package of cheese?

Respuesta :

The combined cost of one loaf of bread and one package of cheese is [tex]\boxed{\$ 6.5}.[/tex]

Further explanation:

Explanation:

Consider the cost of one loaf of bread as [tex]x.[/tex]

Consider the cost of one package of cheese as [tex]y.[/tex]

Mason bought 6 loaves of bread and 3 packages of cheese for a total of [tex]\$27.[/tex]

[tex]\begin{aligned}6x + 3y &= 27\\\frac{{6x}}{3} + \frac{{3y}}{3} &= \frac{{27}}{3}\\2x + y &= 9\\y + 2x &= 9\\\end{aligned}[/tex]

The cost of a package of cheese is [tex]\$1.50[/tex] more than the cost of a one loaf of bread.

[tex]y = 1.5 + x[/tex]

Substitute [tex]1.5 + x[/tex] for y in equation [tex]y + 2x = 9.[/tex]

[tex]\begin{aligned}1.5 + x + 2x &= 9\\1.5 + 3x &= 9\\3x &= 9 - 1.5\\3x &= 7.5 \\ x &= \frac{{7.5}}{3} \\ x &= 2.5\\\end{aligned}[/tex]

The cost of one package of cheese can be obtained as follows,

[tex]\begin{aligned}y&= 1.5 + 2.5\\&= 4\\\end{aligned}[/tex]

The combined cost of one loaf of bread and one package of cheese can be obtained as follows,

[tex]\begin{aligned}x + y &= 2.5 + 4\\&= 6.5\\\end{aligned}[/tex]

The combined cost of one loaf of bread and one package of cheese is [tex]\boxed{\$ 6.5}.[/tex]

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Answer details:

Grade: High School

Subject: Mathematics

Chapter: Linear equation

Keywords: Mason, 6, loaves, bread, packages, cheese, total, $27, loaf, combined, cost, bought, $1.50, loaves of bread, packages of cheese, combined cost, one loaf of bread, one package of cheese, cheese is $1.50 more.

Combined cost of one loaf of bread and one package of cheese= $6.5

Step-by-step explanation:

Given :

Total cost of 6 loaf of bread and 3 packages of cheese is $27.

The cost of a package of cheese is $1.50 more than the cost of a one loaf of bread.

Calculation :

Let the cost of one loaf of bread as x and the cost of one package of cheese as y.

Now,

[tex]6x+3y=27[/tex]  ------ (1)

[tex]y=1.5+x[/tex] ----- (2)

Now solving equation (1) and (2) we get x and y,

[tex]6x + 3(x+1.5) =27[/tex]

[tex]9x+4.5=27[/tex]

[tex]x=2.5[/tex]  ----- (3)

[tex]y = 4[/tex]             (from equation (2) and (3))

Combined Cost = $6.5

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