Answer: [tex]x=-\frac{13}{16}[/tex]
Step-by-step explanation:
Here the given equations are,
[tex]y = x^3 + 3[/tex] ------- (1)
[tex]y = x^2 + 2[/tex] ---------(2)
Since we know that the solution of the above equation will find in the intersection point of these equations.
For this we have to solve these equations.
Subtracting equation (1) by equation (2)
We get, [tex]x^3-x^2+1=0[/tex]
⇒ x = -0.75488 ≈ - 0.80
Which is the x-coordinate of the solution of equations f(x) and g(x).
In Options, [tex]-\frac{13}{16}= - 0.8125[/tex]
[tex]-\frac{5}{4}=-1.25[/tex]
[tex]-\frac{15}{16}=-0.9375[/tex]
[tex]-\frac{7}{8}=-0.875[/tex]
Since, Only - 0.8125 is nearby to -0.80.
Thus, the approximate solution of f(x) and g(x) is [tex]-\frac{13}{16}[/tex]
