A spinner divided into four equal parts, A, B, C, and D, is spun, then is followed by a roll of a standard six-sided die.

How many total outcomes are possible?

How many outcomes have an ‘A’ and an odd number?

What is the probability of getting an ‘A’? Getting an odd number? Getting an ‘A’ and an odd number?

P(A)= P(odd)= P(A and odd)=

What is the probability of getting an odd number, given an ‘A’ has already been spun?

P(odd│A)=

Since P(odd│A)=P(odd), are the events independent or not independent?

What is the probability of getting an ‘A’ or an odd number? P(A or odd)=

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tramserran tramserran · Answer 1 · 2019-01-03T08:17:53+01:00

Answer: 24

Step-by-step explanation:

Total Possible Outcomes given A, B, C, D and 1, 2, 3, 4, 5, 6

= 4 x 6

= 24

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Answer: 3

Step-by-step explanation:

Total outcomes for an A and and odd number

= A and (1 or 3 or 5)

= 1 x 3

= 3

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Answer: [tex]\bold{\dfrac{1}{4,}\qquad \dfrac{1}{2,}\qquad \dfrac{1}{8}}[/tex]

Step-by-step explanation:

Probability of an A out of A, B, C, D is: [tex]\dfrac{1}{4}[/tex]

Probability of an odd (1, 3, 5) out of 1, 2, 3, 4, 5, 6 is: [tex]\dfrac{3}{6}=\dfrac{1}{2}[/tex]

Probability of an A and an odd is: [tex]\dfrac{1}{4}\times\dfrac{1}{2}=\dfrac{1}{8}[/tex]

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Answer: [tex]\bold{\dfrac{1}{2}}[/tex]

Step-by-step explanation:

Probability of an odd (1, 3, 5) out of 1, 2, 3, 4, 5, 6 is: [tex]\dfrac{3}{6}=\dfrac{1}{2}[/tex]

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Answer: [tex]\bold{\dfrac{3}{4}}[/tex]

Step-by-step explanation:

Probability of an A or an odd is: [tex]\dfrac{1}{4}+\dfrac{1}{2}=\dfrac{1}{4}+\dfrac{2}{4}=\dfrac{3}{4}[/tex]