Respuesta :
When horizontal force is applied on block then as per Newton's II law we will have
[tex]F = ma[/tex]
[tex]10 = m(5.3)[/tex]
so here mass will be
[tex]m = 1.89 kg[/tex]
now on same block F = 5 N is applied on surface of Moon
so on surface on moon we will have
[tex]F = ma[/tex]
[tex]5 = 1.89 a[/tex]
[tex]a = 2.65 m/s^2[/tex]
so above is acceleration on surface of moon
The rate of change of the velocity is known as the acceleration. The acceleration imparted to the block is 2.65 m/sec².
What is acceleration?
The rate of change of the velocity is known as the acceleration. It is a time-based quantity. Its unit is m/sec².The acceleration is also given by the ratio of force to the mass.
The given data in the problem is;
a is the acceleration of the block= 5.3 m/s²
F is the horizontal force = 10 N
a' is the acceleration due to gravity at the surface of the moon = 1.62
The value of the mass is found by;
[tex]\rm m = \frac{F}{a} \\\\ \rm m = \frac{10}{5.3} \\\\ \rm m =1.89[/tex]
The value of the acceleration is found by;
[tex]\rm F=ma \\\\ \rm a=\frac{F}{m} \\\\ \rm a=\frac{5}{1.89} \\\\ \rm a=2.65\ m/sec^2[/tex]
Hence the acceleration imparted to the block is 2.65 m/sec².
To learn more about the acceleration refer to the link;
https://brainly.com/question/12134554
