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the temperature on the ground during a plane's takeoff was -7degrees.at 38000 feet in the air,the temperature outside the plane was -29 degrees.find the difference between these two temprature.

Respuesta :

wegnerkolmp2741o

Answer:

22 degrees

Step-by-step explanation:

AT y=0  t = -7

at y = 38000 t= -29

What is the difference in temperature

t(0) - t(3800) = -7 - (-29) = -7+29 = 22

The difference is 22 degrees  

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