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A solution contains 225 g of sodium chloride, NaCl, dissolved in enough water to make a 0.25 L of solution. What is the molarity of the solution?

Respuesta :

We know that molarity is the number of moles of solute dissolved per litre of solution

[tex]Molarity=\frac{molesofsolute}{volume-of-solution}[/tex]

Moles = mass / molar mass

molar mass of NaCl = atomic mass of Na + atomic mass of Cl = 23+ 35.5 = 58.5

[tex]moles=\frac{225}{58.5}=3.85[/tex]

therefore

[tex]molarity=\frac{3.85}{0.25}=15.4M[/tex]

Thus molarity of given solution will be 15.4 M

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