Answer: There is total vertical space of 494 feet traveled ascending and descending the entire 15-Stair staircase .
Step-by-step explanation:
Since we have given that
Number of stairs in a staircase is formed = 15
Vertical space between consecutive stairs for the first 10 stairs = 113 feet
Vertical space between consecutive stairs for the last 5 stairs = 134 feet
Total vertical distance traveled ascending the entire 15-stair staircase is given by
[tex]113+134\\\\=247\ feet[/tex]
Total vertical distance traveled ascending and descending the entire 15-stair staircase is given by
[tex]247\times 2=494\ feet[/tex]
Hence, there is total vertical space of 494 feet traveled ascending and descending the entire 15-Stair staircase .
Answer:
The total vertical distance traveled ascending and descending the entire 15-stair staircase is 44.167 feet.
Step-by-step explanation:
It is given that the vertical space between consecutive stairs for the first 10 stairs is
[tex]1\frac{1}{3}=\frac{3+1}{3}=\frac{4}{3}[/tex]
Total vertical distance for first 10-stairs is
[tex]\frac{4}{3}\times 10=\frac{40}{3}[/tex]
The vertical space for the last 5 stairs is
[tex]1\frac{3}{4}=\frac{4+3}{4}=\frac{7}{4}[/tex]
Total vertical distance for 5-stairs is
[tex]\frac{7}{4}\times 5=\frac{35}{4}[/tex]
The total vertical distance of 15-stairs is
[tex]Total=\frac{40}{3}+\frac{35}{4}=\frac{265}{12}[/tex]
Total vertical distance traveled ascending and descending the entire 15-stair staircase is
[tex]\frac{265}{12}\times 2=\frac{265}{6}\approx 44.167[/tex]
Therefore the total vertical distance traveled ascending and descending the entire 15-stair staircase is 44.167 feet.
