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A force of 9.00 newtons acts at an angle of 19.0 to the horizontal. What is its component in the horizontal direction?

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Solution

In this question we have given,

Force, F=9N

angle,α=19degree with horizontal

therefore,

Component of force in horizontal direction is given as

[tex]F_{x} =F\times Cos\alpha[/tex]

[tex]F_{x} =9\times Cos19[/tex]

[tex]F_{x} =9\times .946[/tex]

[tex]F_{x} =8.51N[/tex]

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