An object is 10. cm from the mirror, its height is 3.0 cm, and the focal length is 2.0 cm. What is the image height? (Indicate the object orientation by including the + or - sign with the answer.)

hi = _____ cm

+1.33
-1.33
+0.75
-0.75

Respuesta :

As we know by mirror formula we have

[tex]\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}[/tex]

here we know that

[tex]d_o = 10 cm[/tex]

[tex]f = 2 cm[/tex]

now from above equation

[tex]\frac{1}{10} + \frac{1}{d_i} = \frac{1}{2}[/tex]

here we will have

[tex]d_i = 2.5 cm[/tex]

now for size of image we know that

[tex]\frac{h_i}{h_o} = -\frac{d_i}{d_o}[/tex]

here we will have

[tex]h_i = -3 \times \frac{2.5}{10}[/tex]

[tex]h_i = -0.75 cm[/tex]

Answer:

-0.75

Explanation: