Answer
2.7956 * 10^19 photons
Givens
Formula
E = h * c / λ
W = E / t
Solution
E = 6.26 * 10^-34 j*s * 3 * 10^8 m/s /525 * 10^-9 (m)
The meters cancel out. So do the seconds. You are left with Joules as you should be.
E = 3.577 * 10^-18 Joules
What you have found is the energy of 1 photon.
Now you have to find the Joules from the watts.
W = E/t
100 * 1 second = 100 joules
1 photon contains 3.577 * 10 ^ - 18 Joules
x photon = 100 joules
1/x = 3.577 * 10^-18 / 100 Cross multiply
100 = 3.577 * 10 ^ - 18 * x Divide both sides by 3.577 * 10 ^ - 18
100/3.577 * 10 ^ - 18 = 3.577 * 10 ^ - 18x / 3.577 * 10 ^ - 18
2.7956 * 10^19 photons = x
The number of photons emitted per second will be "[tex]2.6\times 10^{20}[/tex]".
According to the question'
Energy,
Planks constant,
Velocity of light,
Wavelength,
or,
= [tex]525\times \frac{10^{-9}}{1}[/tex]
= [tex]5.25\times 10^{-7} \ m[/tex]
As we know,
→ Energy, [tex]E = n \frac{hc}{\lambda}[/tex]
The number of photons will be:
= [tex]\frac{E \lambda}{hc}[/tex]
= [tex]\frac{100(5.25\times 10^{-7})}{(6.63\times 10^{-34})(3\times 10^8)}[/tex]
= [tex]2.6\times 10^{20}[/tex]
Thus the above solution is correct.
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