lexybellx3
contestada

WORTH 100 POINTS need the answers asap

first row

-x^2
2x^2
(x/2)^2
x^2

x is less than 2
x is greater than 2
x is less than or equal to 2
x is greater than or equal to 2

second row

-5
-5/2
4
5

•2 is less than x&x is less than 4
•2 is less than or equal to x & x is less than or equal to 4
•2 is less than or equal to x&x is less than 4
•2 is less than x&x is less than or equal to 4


WORTH 100 POINTS need the answers asap first row x2 2x2 x22 x2 x is less than 2 x is greater than 2 x is less than or equal to 2 x is greater than or equal to 2 class=

Respuesta :

1Angel2Got3Brains
your sloping right? or n
alinakincsem

Answer:

[tex] f(x) = x^2 , x < 2 [/tex]

[tex] f(x) = 5, 2\leq x < 4 [/tex]

Step-by-step explanation:

We are given a graph with a parabola and a line it it.

The parabola in the given graph goes until x = 2 but is not able to reach that very value. So x = 2 starts on the line above where x = 2 and ends just before the value of x = 4.

Therefore, this can be modeled by:

[tex] f(x) = x^2 , x < 2 [/tex]

[tex] f(x) = 5, 2\leq x < 4 [/tex]

Otras preguntas