Answer:
Probability that both cans were regular soda = [tex]\frac{1}{11}[/tex]
Step-by-step explanation:
Probability = [tex]\frac{Desired outcome}{Total possible outcomes}[/tex]
We are given 12 total number of cans; 4 cans have been accidentally filled with diet soda.
Probability that first can is a regular soda:
Outcome that first can is a regular soda will give us the number of regular soda available which are 4
Using formula of probability
Total possible outcomes are, n(total) = 12
Desired outcome: 4 (cans of regular soda)
P(1st can) = [tex]\frac{4}{12}[/tex] = [tex]\frac{1}{3}[/tex]
Probability that 2nd can is a regular soda:
As we have already taken a can of regular soda from the pack, the total soda in the pack now 11 and the regular soda left are 3.
Total possible outcomes are, n(total) = 11
Desired outcome: 3 (cans of regular soda as one has already been taken)
P(2nd can) = [tex]\frac{3}{11}[/tex]
Probability that both cans are regular soda:
P(both) = P(1st can) × P(2nd can)
= [tex]\frac{1}{3} * \frac{3}{11}[/tex]
= [tex]\frac{1}{11}[/tex]
Answer:
1/11
Step-by-step explanation:
We know that 4 cans filled with regular soda were labelled diet soda and placed in a 12 pack carton.
Two cans were picked randomly and we are to find the probability that both cans were of regular soda.
No. of cans with regular soda = 4
No. of cans with diet soda = 8
P (both cans regular soda) = 4/12 * 3/11 = 1/11
