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If I make a solution by adding 83grams of sodium hydroxide to 750mL I’d water what is the molarity of sodium hydroxide

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Answer:

2.8 mol·L⁻¹

Step-by-step explanation:

1. Convert grams to moles.  

Moles NaOH = 83 g NaOH × (1 mol NaOH /40.00 g NaOH)

                     = 2.08 mol NaOH

2. Convert millilitres to litres  

V = 750 mL × (1 L/1000 mL)

  = 0.7500 L

3. Calculate the molar concentration (c)  

c = moles/litres = 2.08 mol/0.7500 L

  = 2.8 mol/L

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