[tex]\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$25000\\ r=rate\to 1.4\%\to \frac{1.4}{100}\dotfill &0.014\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &15 \end{cases}[/tex]
[tex]\bf A=25000\left(1+\frac{0.014}{1}\right)^{1\cdot 15}\implies A=25000(1.014)^{15}\implies A\approx 30797.0653[/tex]
