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Evaluate the discriminant of each equation. Tell how many solutions each equation has and whether the solutions are real or imaginary.

x^2 + 4x + 5 = 0

Respuesta :

Answer:

solutions are imaginary

Step-by-step explanation:

[tex]x^2 + 4x + 5 = 0[/tex]

Given equation is in the form of ax^2 + bx+c=0

a= 1 , b= 4  and c= 5

Discriminant is [tex]b^2 - 4ac[/tex]

Plug in the values

D= [tex]b^2 - 4ac[/tex] = [tex]4^2 - 4(1)(5)= -4[/tex]

Discriminant D = -4 that is negative

When Discriminant is negative then the solutions are imaginary

zainebamir540

Answer:

Discriminant is -4.

x²+4x+5  = 0 have two imaginary solutions

Step-by-step explanation:

Given equation is :

x²+4x+5  = 0

ax²+bx+c  = 0 is general quadratic equation.

comparing given equation with quadratic equation,we get

a  = 1 ,b  = 4 and c  = 5

the formula to find discriminant is

D   = b²-4ac

putting above values in formula of discriminant,we get

D  = (4)²-4(1)(5)

D  = 16-20

D  = -4 < 0

The discriminant of given equation is not real hence, given equation have two imaginary solution .

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