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A sample of the male sex hormone testosterone, C19H28O2, contains 3.88×10^21 atoms of hydrogen.


(a) How many atoms of carbon does it contain?

(b) How many molecules of testosterone does it contain?

(c) How many moles of testosterone does it contain?

(d) What is the mass of this sample in grams?

Respuesta :

Answer:

i think its a

Explanation:

There are [tex]2.63\times 10^{21}[/tex] atoms of carbon.

It contains [tex]1.38\times 10^{20}[/tex] molecules of testosterone.

It contains 0.0000229 moles of testosterones.

0.0661 grams is the mass of this sample of testosterone.

Explanation:

Given:

The molecular formula of testosterone, [tex]C_{19}H_{28}O_2[/tex]

The [tex]3.88\times 10^{21}[/tex]atoms of hydrogen.

To find:

The number of carbon atoms

The number of molecules of testosterone

The moles of testosterone

Mass of testosterone in grams

Solution

The molecular formula of testosterone=[tex]C_{19}H_{28}O_2[/tex]

The number of hydrogen atoms =[tex]3.88\times 10^{21} atoms[/tex]

The carbon to hydrogen atom ratio:

[tex]C:H=\frac{19}{28}[/tex]

The carbon atoms associated with testosterone's molecules hydrogen atom =x

[tex]\frac{x}{ 3.88\times 10^{21} atoms }=\frac{19}{28}\\x=\frac{19}{28}\times 3.88\times 10^{21} atoms =2.63\times 10^{21} atoms[/tex]

There are [tex]2.63\times 10^{21}[/tex] atoms of carbon.

The molecular formula of testosterone= [tex]C_{19}H_{28}O_2[/tex]

The number of hydrogen atoms = [tex]3.88\times 10^{21} atoms[/tex]

The number of testosterone molecules = N

In one molecule of testosterone, there are 28 atoms of hydrogen. Then in N number of testosterone molecules, there will be:

[tex]3.88\times 10^{21} atoms=N \times 28\\N=\frac{ 3.88\times 10^{21} atoms }{28}=1.38\times 10^{20} molecules[/tex]

It contains [tex]1.38\times 10^{20}[/tex] molecules of testosterone.

The number of testosterone molecules = [tex]N = 1.38\times 10^{20} molecules[/tex]

The moles of testosterone = n

According to the mole concept:

[tex]N=n\times N_A\\1.38\times 10^{20} molecule=n\times 6.022\times 10^{23} molecules\\n=\frac{1.38\times 10^{20} molecule}{6.022\times 10^{23} molecule}\\n=0.000229 mol[/tex]

It contains 0.0000229 moles of testosterones.

The moles of testosterone = 0.000229 mol

The molar mass of testosterone:

[tex]=12.01 g/mol\times 19+1.008g/mol\times 28+16.00\times g/mol\times 2\\=288.414 g/mol[/tex]

The mass of 0.000229 moles of testosterone:

[tex]=0.000229 mol\times 288.414 g/mol=0.0661 g[/tex]

0.0661 grams is the mass of this sample of testosterone.

Learn more about the mole concept here:

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