The perimeter of a triangle is 69 cm. the first is 5 cm shorter than the second side. the third side is twice as long the first side. find the length of each side

Respuesta :

Answer:

Side a = 23 Side b = 28  Side c =46

Step-by-step explanation:

First set up your equation witch is x-5+x+x-5*2=69

Then Simplify x+-5+x+x+-10=69

Then combine like terms 3x-15=69

Add 15 to both sides

After you will get 3x=84

then divide both sides by 3

You will get x=28

Then go back to your question it says THE FIRST IS 5 CM SHORTER THAN THE SECOND SIDE. THE THIRD SIDE IS TWICE AS LONG AS THE FIRST SIDE. So that tells you that to find A, you do 28-5=23, to side b is x so its 28, and to find side c you do 28-5*2=46. So A=23, B=28, and C=46.