Answer:
The number of adult tickets are 33 and the number of student tickets are 21 .
Step-by-step explanation:
As
The number of adult tickets x and the number of student tickets y.
As given
A carnival sold tickets for $1.50 for adults and $1.00 for students.
There were 54 tickets sold for a total of $70.50.
Equations becomes
x + y = 54
1.50x + 1.00y = 54 × 70.50
Simplify the above
[tex]\frac{150x}{100} + \frac{100y}{100} = \frac{7050}{100}[/tex]
150x + 100y =7050
Two equations are
x + y = 54
150x + 100y =7050
Multiply x + y = 54 by 150 from 150x + 100y =7050
150x - 150x + 100y - 150y = 7050 - 8100
-50y = -1050
50y = 1050
[tex]y = \frac{1050}{50}[/tex]
y = 21
Putting the value of y in the equation .
x + 21 = 54
x = 54 - 21
x = 33
Therefore the number of adult tickets are 33 and the number of student tickets are 21 .
