Answer:
4 seconds
Step-by-step explanation:
Given : [tex]H = -16t^{2} +64t[/tex]
To Find: How many seconds does it take for the golf ball to hit the ground?
Solution :
Since we are given an equation : [tex]H = -16t^{2} +64t[/tex]
Where H denotes height
t denotes the number of seconds elapsed since the ball was hit.
When he golf ball to hit the ground at that time the height becomes 0
So, put H = 0 in the equation
[tex]H = - 16t^{2} +64t[/tex]
[tex]0 = - 16t^{2} +64t[/tex]
[tex]16t^{2} = 64t[/tex]
[tex]16t = 64[/tex]
[tex]t =\frac{64}{16}[/tex]
[tex]t =4[/tex]
Thus it take 4 seconds for the golf ball to hit the ground
