Answer:
If y = 3 both the triangles are congruent and perimeter of Δ PQR = 17 ft.
Step-by-step explanation:
If the given triangles in the figure are congruent then all the corresponding sides of the triangles will be in the same ratio or should be equal.
Therefore for the congruence of these two triangles PR = SU
3y - 2 = y + 4
3y - y = 2 + 4
2y = 6 ⇒ y = 6÷2 = 3
For the value y = 3 both the triangles are congruent.
Perimeter of triangle PQR = Total of all sides = 4 + 6 + (3y-2)
= 8 + 3y
If y = 3 then perimeter of Δ PQR = 8 + 9 = 17
