ANSWER
[tex](3, \infty )[/tex]
EXPLANATION
The given function is
[tex]f(x) = \frac{ {x}^{2} - 9}{x - 3} [/tex]
When we plug in x=3 into this function, we obtain,
[tex]f(3) = \frac{0}{0} [/tex]
This means that the function is discontinuous at x=3.
We need to simplify the function to obtain,
[tex]f(x) = \frac{(x - 3)(x + 3)}{(x - 3)} [/tex]
This implies that,
[tex]f(x) = x + 3[/tex]
The graph this function is a straight line that is continuous everywhere.
To graph
[tex]f(x) = \frac{ {x}^{2} - 9}{x - 3} [/tex]
we draw the graph of
[tex]f(x) = x + 3[/tex]
and leave a hole at x=3.
See diagram in attachment.
Hence the coordinates of hole is
[tex](3, \infty )[/tex]
