So lets list out we have here:
velocity = 62 m/s
Force = 272 N
Mass = 0.058kg
In studying momentum you learn that the force multiplied by the change in time is equal to the change in momentum.
FΔt = Δp
FΔt = p(final) - p(initial)
The ball is orginally at rest so its momentum is zero because momentum = mass x velocity and if velocity is 0 then the whole equation goes to zero. So...
FΔt = p(final)
Isolating for Δt gives
Δt = p(final) / F
Δt = mv / F
Δt = (0.058)(62) / (272)
Δt = 0.013 seconds
The time of contact will be 0.013 sec.Principal of the Newtons second law is applied in given problem.
The measurement of mass in motion is called momentum. Momentum is equal to its mass multiplied by its velocity. Mathematically it is given as;
Momentum = Mass x Velocity
The given data in the problem is
ball mass ( m)= 0.058 Kg
speed of the ball(v) = 62.0m/s
Force = 272 N
From the Newton's second law;
FΔt = Δp
FΔt = p(final) - p(initial)
Because the ball is at rest, its momentum is zero.
FΔt = p(final)
The time period of contact with the ball is found as;
[tex]\rm \triangle t= \frac{P_{final}}{F} \\\\ \rm \triangle t= \frac{mv}{F} \\\\ \triangle t=\frac{0.058 \times 62 }{272} \\\\\ \triangle t= 0.013 seconds[/tex]
Hence,the time of contact will be 0.013 sec.
To learn more about the momentum refer to the link;
https://brainly.com/question/4956182
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