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A solution is prepared using 0.125 glucose C6H12O6 is enough water to make 250 g of total solution the concentration of the solution, expressed in parts per million is

Respuesta :

Answer : The concentration of solution in ppm is, 500 ppm

Solution : Given,

Mass of solute (glucose) = 0.125 g

Mas of solution = 250 g

Parts per million (ppm) : It is defined as the mass of a solute present in one million [tex](10^6)[/tex] parts by the mass of the solution.

Formula used :

[tex]ppm=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6[/tex]

Now put all the given values in this formula, we get

[tex]ppm=\frac{0.125g}{250g}\times 10^6=500ppm[/tex]

Hence, the concentration of solution in ppm is, 500 ppm

The concentration of the solution, expressed in parts per million (ppm) is 500 ppm

From the question given above, the following data were obtained:

  • Mass of solute (glucose) = 0.125 g
  • Mass of solution = 250 g
  • Concentration (ppm) =?

Concentration of the solution in ppm can be obtained as follow:

Concentration = (mass of solute / mass of solution) × 10⁶

Concentration = (0.125/250) × 10⁶

Concentration = 500 ppm

Therefore, the concentration of the solution in ppm is 500 ppm

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