Respuesta :

carlosego

Answer: [tex](y+4)=-3(x+8)[/tex]

Step-by-step explanation:

The equation of the line is point-slope form is:

[tex](y-y_1)=m(x-x_1)[/tex]

Where m is the slope of the line and ([tex]x_1,y_1[/tex]) is a  point of the line.

You know that the slope is -3 and the problem gives you the point (-8,-4), therefore you only need to substitute them into the equation shown above.

Then, you obtain:

[tex](y-(-4))=-3(x-(-8))[/tex]

[tex](y+4)=-3(x+8)[/tex]

zainebamir540

Answer:

y+4  = -3(x+8)

Step-by-step explanation:

We have given slope of a line and a point that passes through the line.

slope  = m = -3   and (x₁,y₁)  = (-8,-4)

We have to find the point-slope form of the line.

y-y₁  = m(x-x₁) where m is slope and (x₁,y₁) is a point that passes through the line.

Putting given values in point-slope form ,we have

y-(-4)  = -3(x-(-8))

y+4  = -3(x+8) is point slope form of line having slope equal to -3 and that passes through the point (-8,-4).

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