Answer:
640 m.
Step-by-step explanation:
D = kt^2 where d is the constant of proportionality.
D = 80 m when t = 4 seconds so:
80 = k*4^2
k = 80 / 16 = 5.
So the equation of motion is D = 5t^2.
When t = 8+4 = 12 seconds D = 5*12^2 = 5*144
= 720 m
So the distance the ball drops in the next 8 seconds = 720 - 80
= 640 m.
The distance covered by the ball in the next 8 seconds will be 320 meters.
Given information:
A ball, dropped vertically, falls D meters in t seconds.
D is directly proportional to the square of t.
The ball drops 80 meters in the first 4 seconds.
So, the relation between D and t can be written as,
[tex]D\propto t^2\\D=kt^2[/tex]
where k is the constant.
Now, from the given condition, the value of k can be calculated as,
[tex]D=kt^2\\80=k\times 4^4\\k=5[/tex]
Now, the distance covered by the ball in the next 8 seconds will be,
[tex]D=5t^2\\D=5\times 8^2\\D=320[/tex]
Therefore, the distance covered by the ball in the next 8 seconds will be 320 meters.
For more details, refer to the link:
https://brainly.com/question/18082683
