Part A
F = 50 N is the force applied along the purple vector
r = 1.5 is the radius (half the diameter 3)
theta = 110 is the angle in which the force vector is applied
Use this formula to plug in the values to find the torque T
T = F*r*sin(theta)
T = 50*1.5*sin(110)
T = 70.4769
Answer: The torque applied is approximately 70.4769 Newton-meters
=========================================
Part B
Refer back to the formula in part A. If theta is the variable, then T maxes out when theta = 90 degrees, because sin(theta) is maxed out at 1 here. If theta = 90, then T = F*r. The torque is maxed out when the force vector is perpendicular to the original position vector, this way you get the most push leading to the highest twisting or turning force possible.
Answer: 90 degrees
=========================================
Part C
Use the values from part A, but make theta = 90 so that the torque T is maxed out. So we would get the following
T = F*r*sin(theta)
T = 50*1.5*sin(90)
T = 50*1.5*1
T = 75
Answer: The max torque possible is 75 Newton-meters
