Answer:
Step-by-step explanation:
The answers to A and B are both 1 when n = 1. Try it.
f(n) = 3^n
f(1) = 3^(1 - 1)
f(1) = 3^0 Anything to the 0 (except 0) = 1 (18.4344423432)^0 = 1
So when n = 1 both A and B go to 1.
I think you will find that C is the correct answer.
f(2) = 6(3^(2 - 1)
f(2) = 6( 3^1)
f(2) = 6*3
f(2) = 18
If you follow the same steps for D you will find the n = 3 won't work
f(3) = 2*(6^(3 - 1))
f(3) = 2*(6^2)
f(3) = 2* 36
f(3) = 72 which is not 54.
Answer C
