Respuesta :

carlosego

Answer:

[tex]x=1\\y=1\\\\(1,1)[/tex]

Step-by-step explanation:

Apply the method of  substitution:

- Substitute [tex]x=2y-1[/tex] into the first equation:

[tex]2(2y-1)+y=3\\4y-2+y=3\\5y=5\\y=1[/tex]

- Substitute the value of y into the any of the original equations and solve for x, as you can see below:

[tex]1=2y-1\\2=2y\\y=1[/tex]

Then the solution is:

[tex]x=1\\y=1\\\\(1,1)[/tex]

zainebamir540

Answer:

The solution is (1,1).

Step-by-step explanation:

We have given a system of equations.

2x+y = 3               eq(1)

x = 2y-1               eq(2)

We have to find the solution of given system.

Putting eq(2) into eq(1), we have

2(2y-1)+y = 3

4y-2+y = 3

4y+y = 3+2

Adding like terms, we have

5y =  5

y = 1

Putting value of y in eq(2) , we have

x = 2(1)-1

x = 2-1

x = 1

Hence , the solution is (1,1).

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