QUESTION 1
The tangent ratio is the ratio of the length of the opposite side to the length of the adjacent side.
[tex] \tan(M) = \frac{LN}{NM} [/tex]
[tex] \tan(M) = \frac{8}{6} = \frac{4}{3} [/tex]
QUESTION 2.
We again use the tangent ratio to find angle S.
[tex] \tan(S) = \frac{TU}{SU} [/tex]
[tex]\tan(S) = \frac{0.75}{3.5} [/tex]
[tex]\tan(S) = \frac{3}{14} [/tex]
[tex]S = { \tan}^{ - 1} ( \frac{3}{14} )[/tex]
[tex]S = 12.09 \degree[/tex]
to the nearest hundredth.
QUESTION 3
We can find CE using the tangent ratio.
[tex] \tan(27 \degree) = \frac{18}{CE} [/tex]
[tex]CE = \frac{18}{ \tan(27 \degree) } [/tex]
[tex]CE = 35.3 \degree[/tex]
to the nearest 0.1.
