Answer:
47.67%
Step-by-step explanation:
Amount of 1st solution = 9 ml
Let the percentage acid concentration of 1st solution is x%
Amount of 2nd solution = 8 ml
Percentage acid concentration of 2nd solution = 42%
Percentage acid concentration of the mixture = 45%
Amount of the mixture = 8 + 9 = 17 ml
1st Solution + 2nd Solution = Mixture
x% of 9 ml + 42% of 8 ml = 45% of 17 ml
[tex]0.09x + 3.36 = 7.65\\\\ 0.09x = 7.65 - 3.36\\\\ 0.09x = 4.29\\\\ x = \frac{4.29}{0.09}\\\\ x = 47.67[/tex]
Thus, the percent acid concentration of first solution is 47.67%
