Answer:
[tex]\large\boxed{7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}=\sqrt[3]{2x}-6\sqrt[3]{x}}[/tex]
Step-by-step explanation:
[tex]7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}\\\\=7\sqrt[3]{2x}-3\sqrt[3]{(8)(2x)}-3\sqrt[3]{8x}\qquad\text{use}\ \sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}\\\\=7\sqrt[3]{2x}-3\sqrt[3]8\cdot\sqrt[3]{2x}-3\sqrt[3]8\cdot\sqrt[3]{x}\\\\=7\sqrt[3]{2x}-3(2)\sqrt[3]{2x}-3(2)\sqrt[3]{x}\\\\=7\sqrt[3]{2x}-6\sqrt[3]{2x}-6\sqrt[3]{x}\\\\=\sqrt[3]{2x}-6\sqrt[3]{x}[/tex]
